Share Improve this answer To get the pointer to next string, increment this pointer adding exactly 4. Summary: In this programming tutorial, we will learn different ways to convert a number of type int into a char pointer or array in C++. In C++11, a move constructor of std::vector<T> that takes an rvalue reference to an std::vector<T> can copy the pointer to the internal C-style array out of the rvalue into the new std::vector<T>, then set the pointer inside the rvalue to null. So would it be fair to say that what std::move does is just call move constructor and if not's available call copy constructor? Don't use memcpy. Convert pointer to uintptr_t constexpr context : cpp_questions We can easily get a const char* from the std::string in constant time with the help of the string::c_str function. Here's how the code would look like: Or dynamically create a character array of size n+1 for a string of length n and include null-terminating character to be safe, as shown below: Below is the implementation of the above approach. Remember that the name of an array is equivalent to &array [0], i.e. Copy Code. If you intend to modify data stored at the pointer returned by the c_str () method, first, you must copy the range . 1. char *input_cr; input_cr=(char*) &data; Serial.println("Converted"); Serial.print(input_cr); double balance [50]; balance is a pointer to &balance [0], which is the address of the first element of the array balance. C++11 - Wikipedia 43°NE; Perpetual motion; Archipelago This post will discuss how to convert a string to a char array in C++. 1.使用する std::string::copy. char *string=malloc (10 * sizeof (char)); but i thought I could do the same defining a pointer to char, a char array and make the pointer points to the first character of the char array. These are often used to create meaningful and readable . You can store the reference of this by simply doing char* c = 'c'; char &ref = c; but this would be absolutely pointless and leading to nowhere.